230V Mains Operated 50 LEDs Circuit Without any Capacitor

How to make the Rice 50LEDs chain

Component Requirement :-       1)     50LEDs

                                         2)     3K /or 2.7K. Resistor

                                         3)     Bridge rectifier

                                           (4xIN4007 Diode )

                                         4)     As required wire.

*To find out resistance value Use this formula:- R= Vs-(Vf×Total number of led in series) /I R= Resistance/Resistor. Vs= supply Voltage. Vf= Forward Voltage of single Led/forward voltage drop by single Led. I= Current consume by single Led/Led Ampere. Ex:- supply Voltage= 200V AC Forward voltage of single 5mm 2pin RGB Led= 3.6V, Total number of led Led current= 200mA/0.02A Ex= 200-(3.6×50) /0.02 R= 100 ohm = 1Kohm. To find out Resistance wattage R = Vs-(Vf×50) ×I R= 200-(3.6×50) 0.02 R= 0.4 means quarter watt or 1/4watt you can use half watt for batter current limit

*Connection Diagram :- 

Connection Instructions:-

Here in Fig show 9 LEDs,  but actual circuit have a 50 LEDs.

and Frist 3 led connect via 3k/2.7k resistace use,It's mandatory in this circuit.

       

          If you have any doubts, you can comment. I will reply soon🙏